Given side of cube = 3.4 inches
Considering 3.4 as 'a'
So,
[tex] {a}^{3} = volume[/tex]
[tex] = > 3.4 \times 3.4 \times 3.4 = volume[/tex]
[tex] = > 39.304in^{3} [/tex]
Now,
[tex]6 {a}^{2} = [/tex]surface area
[tex] = > 6 \times (3.4)^{2} = [/tex]surface area
[tex] = > 69.36in^{2} [/tex]
Therefore,
Volume of cube = 39.304 in^3
Surface area of cube = 69.36 in^2
