Answer:
• let f(x) be y:
• Here, we shall use product rule
[tex]{ \boxed{ \bf{ \frac{dy}{dx} = { \huge{v} } \frac{du}{dx} + { \huge{u}} \frac{dv}{dx} }}} \\ [/tex]
- v is (x - 4)
- u is (x + 1)
- du/dx is 1
- dv/dx is 1
[tex]{ \rm{ \frac{dy}{dx} = (x - 4) + (x + 1)}} \\ \\ { \rm{ \frac{dy}{dx} = 2x - 3}}[/tex]
