caradut3838
caradut3838 caradut3838
  • 26-10-2021
  • Mathematics
contestada

I need help with Special Right Triangles. Thanks :)

I need help with Special Right Triangles Thanks class=

Respuesta :

yathicha
yathicha yathicha
  • 26-10-2021

Answer: c

Step-by-step explanation:

sin(45) =  [tex]\frac{12}{AB}[/tex]

sin(45) = [tex]\frac{\sqrt{2} }{2}[/tex]

so [tex]\frac{\sqrt{2} }{2} =\frac{12}{AB}[/tex]

[tex]AB = \frac{24}{\sqrt{2} }[/tex]

[tex]AB = (\frac{24}{\sqrt{2} }) (\frac{\sqrt{2} }{\sqrt2} } )[/tex]

[tex]AB = \frac{24\sqrt{2} }{2}[/tex]

[tex]AB= 12\sqrt{2}[/tex]

Please give me a brainliest answer

Answer Link
Аноним Аноним
  • 30-10-2021

[tex]\\ \sf\longmapsto cos45=\dfrac{CB}{AB}[/tex]

[tex]\\ \sf\longmapsto \dfrac{1}{\sqrt{2}}=\dfrac{12}{AB}[/tex]

[tex]\\ \sf\longmapsto AB=12\sqrt{2}[/tex]

Answer Link

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