Answer:
Step-by-step explanation:
[tex]1.\\f(x)=e^x\\f'(x)=e^x\\2.\\y=x^8-12x^5-3x^2+7x+22\\\frac{dy}{dx}=8x^7-12*5 x^4-3*2x+7+0\\\frac{dy}{dx}=8x^7-60 x^4-6x+7\\3.\\f(x)=e^3\\f'(x)=0[/tex]
