Respuesta :

priyodiptobasak

Step-by-step explanation:

considering, ∆ABE and ∆ CDE.

(I) BE=DE (S),

(II) AE=EC (S),

(III) <AEB=<CED (Vertically opposite angle) [A].

So, by A.A.S. criterion we can prove that ∆ABE~=∆CDE.

hope my answer helps you.

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