Answer:
x=9
Step-by-step explanation:
4^(3x - 5) = (16)^(x+2)
Rewrite 16 as 4^2
4^(3x - 5) = 4^2^(x+2)
We know a^b^c = a^(b*c)
4^(3x - 5) = (2)^(2*(x+2))
4^(3x - 5) = (4)^(2x+4)
The bases are the same so the exponents are the same
3x-5 = 2x+4
Subtract 2x from each side
3x-5-2x = 2x+4-2x
x-5 = 4
Add 5 to each side
x-5+5 =4+5
x=9
