Answer:
x=13,y=0
Step-by-step explanation:
We are given a system of equations
[tex] {x}^{2} + {y}^{2} = 169 - - eqn \: 1 \\ 3x + 2y = 39 - - eqn \: 2[/tex]
For equation 1,square all terms to reduce it
√x²+√y²=169
x+y=13
Make x the subject as required by the question to use substitution method
x=13-y
Plug x=13-y into eqn 2
3(13-y)+2y=39
39-3y+2y=39
39-y=39
y=39-39=0
Plug y=0 into equation 1
x+0=13
x=0
