Respuesta :

[tex]\\ \sf\longmapsto \dfrac{4x+2}{x-9}=\dfrac{3}{5}[/tex]

[tex]\\ \sf\longmapsto 5(4x+2)=3(x-9)[/tex]

[tex]\\ \sf\longmapsto 20x+10=3x-27[/tex]

[tex]\\ \sf\longmapsto 20x-3x=-27-10[/tex]

[tex]\\ \sf\longmapsto 17x=-37[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{-37}{17}[/tex]

smritimaharjan7425

Answer:

[tex]\frac{4x+2}{x-9}[/tex] = [tex]\frac{3}{5}[/tex]

5( 4x+ 2 ) = 3 ( x-9 )

20x + 10 = 3x - 27

20x -3x = -27 -10

17x = -37

x = - 37/17

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