cristophermacario198
cristophermacario198 cristophermacario198
  • 28-07-2021
  • Physics
contestada

A car travels initially at 24 m/s, until it enters the highway. If the car accelerates at 4 m/s^2 for a 96 meters, what is the car's new velocity?

Respuesta :

Аноним Аноним
  • 28-07-2021
  • initial velocity=u=24m/s
  • Acceleration=a=4m/s^2
  • Distance=s=96m
  • Final velocity=v

Using 3rd equation of kinematics

[tex]\boxed{\Large{\sf v^2-u^2=2as}}[/tex]

[tex]\\ \Large\sf\longmapsto v^2=u^2+2as[/tex]

[tex]\\ \Large\sf\longmapsto v^2=24^2+2(4)(96)[/tex]

[tex]\\ \Large\sf\longmapsto v^2=576+768[/tex]

[tex]\\ \Large\sf\longmapsto v^2=1344[/tex]

[tex]\\ \Large\sf\longmapsto v=\sqrt{1344}[/tex]

[tex]\\ \Large\sf\longmapsto v=36.6m/s[/tex]

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