estefanimo0528 estefanimo0528
  • 27-07-2021
  • Mathematics
contestada

Can someone help me with this

Can someone help me with this class=

Respuesta :

Luv2Teach
Luv2Teach Luv2Teach
  • 27-07-2021

Answer:

Step-by-step explanation:

The formula for this, specific to our circle, is

∠RQP = [tex]\frac{1}{2}[/tex](arc SP - arc RP) and filling in:

∠RQP = [tex]\frac{1}{2}(170-86)[/tex] and

∠RQP = [tex]\frac{1}{2}(84)[/tex] so

∠RQP = 42°

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