Answer: 48 dimes, 15 quarter
Step-by-step explanation:
Given
The money is of the net worth of [tex]\$8.55[/tex]
If there is total of 63 coins
Suppose there are [tex]x[/tex] dimes and [tex]y[/tex] quarter
[tex]\therefore x+y=63\quad \ldots(i)\\\Rightarrow 0.1x+0.25y=8.55\quad \ldots(ii)[/tex]
Solve (i) and (ii)
[tex]x=48,y=15[/tex]
Thus, there are 48 dimes and 15 quarters
