kyrabright187
kyrabright187 kyrabright187
  • 29-06-2021
  • Mathematics
contestada

i really need help, please​

i really need help please class=

Respuesta :

PriyAnjalee
PriyAnjalee PriyAnjalee
  • 29-06-2021

here, base(b)=7, perpendicular(p)=8 and hypotenuse(h)=?(c)

by using pythagoras theorem.

h^2=p^2+b^2

or,h^2=8^2+7^2

or,h^2=113

or,h=

[tex] \sqrt{113} [/tex]

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