Answer:
0.0036 moles of NaOH are present
Explanation:
A solution of 0.1mol/dm³ contains 0.1 moles of solute (In this case, NaOH), per 1 dm³ of solution.
36cm³ are in dm³ (1000cm³ / 1dm³):
36cm³ * (1dm³/1000cm³) = 0.036dm³
The moles are:
0.036dm³ * (0.1mol/dm³) = 0.0036 moles of NaOH are present
