Respuesta :

sreedevi102

Answer:

LHS ≠ RHS

Step-by-step explanation:

[tex]LHS =\\\\=(x+1)^2 (x + 2) \\\\=(x^2 + 2x + 1)(x+2)\\\\=x(x^2 + 2x + 1) + 2(x^2 + 2x + 1) \\\\=(x^3 + 2x^2 + x ) + ( 2x^2 + 4x + 2) \\\\=x^3 + 2x^2 + x + 2x^2 + 4x + 2 \\\\=x^3 + 4x^2 + 5x + 2[/tex]