9514 1404 393
Answer:
C
Step-by-step explanation:
A root with a given index is the same as a fractional power with that index as the denominator.
[tex]\dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}=6^{\frac{1}{4}}2^{-\frac{1}{3}}=\sqrt[12]{(6^{\frac{1}{4}}2^{-\frac{1}{3}})^{12}}=\sqrt[12]{6^32^{-4}}\\\\=\sqrt[12]{6^32^82^{-12}}=\dfrac{\sqrt[12]{6^32^8}}{2}=\boxed{\dfrac{\sqrt[12]{55296}}{2}}[/tex]
