Answer:
When y=10,x=1 and when y=1,x=10
Explanation:
Log x + log y is the same as log (xy)
x+y=11
x=11-y
So,
log[(11-y)y]=1
log[11y-y^2]=1
The log is to base 10,therefore we can rewrite it in exponential form.
10^1=11y-y^2
y^2-11y+10=0
After solving it we obtain y=10,y=1
When y=10:
x=11-10=1
When y=1
x=11-1=10
Hope it helps:)
