Let u = (1, 0) and v = (0, 1). Then
T (u) = (2*1 - 3*0, 1 + 4, 5*0) = (2, 5, 0)
T (v) = (2*0 - 3*1, 0 + 4, 5*1) = (-3, 4, 5)
=> T (u) + T (v) = (-1, 9, 5)
but
T (u + v) = T (1, 1) = (2*1 - 3*1, 1 + 4, 5*1) = (-1, 5, 5)
=> T (u + v) ≠ T (u) + T (v)
which means T does not preserve addition, so it is not linear.
