Respuesta :

bhadelsimron19

Answer:

Step-by-step explanation:

(x-2)(2x+3)(x+1)

=x(2x+3)-2(2x+3)(x+1)

=(2x^2+3x-4x-6)(x-1)

=(2x^2-x-6)(x-1)

=2x^2(x-1)-x(x-1)-6(x-1)

=2x^3-2x^2-x^2+x-6x+6

=2x^3-3x^2-5x+6

hnori22003

( x - 2 )( x + 1 )( 2x + 3 ) =

( x^2 - x - 2 )( 2x + 3 ) =

2x^3 - 2x^2 - 4x + 3x^2 - 3x - 6 =

2x^3 + ( -2 + 3 )x^2 + ( - 4 - 3 )x - 6 =

2x^3 + x^2 - 7x - 6

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