Respuesta :

Answer:

8x²+16x+8=0

x²+2x+1=0

D=4-4=0

x0=-2/2=-1

unicorn3125

Answer:

        x = -1

Step-by-step explanation:

[tex]8x^2+16x+8=0[/tex]                  {divide both sides by 8}

[tex]x^2+2x+1=0\\\\a=1\,,\quad b=2\,,\quad c=1\\\\x=\dfrac{-2\pm\sqrt{2^2-4\cdot1\cdot1}}{2\cdot1}=\dfrac{-2\pm\sqrt{4-4}}2=\dfrac{-2\pm0}2=-1[/tex]

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