jaimelyne2005
jaimelyne2005 jaimelyne2005
  • 29-04-2021
  • Mathematics
contestada

What is the absolute maximum or minimum of f(x) = 3x^2-5x-9

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goddessboi goddessboi
  • 29-04-2021

Answer:

Absolute minimum / vertex = (5/6,-133/12)

Step-by-step explanation:

Since a is positive, then the absolute maximum is ∞. The absolute minimum would be the vertex of the parabola, meaning x=-b/2a=-(-5)/2(3)=5/6, and y=3(5/6)^2-5(5/6)-9 = -133/12. Therefore, your absolute minimum / vertex is (5/6,-133/12)

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robertsonbri92
robertsonbri92 robertsonbri92
  • 29-04-2021
(5/6,-133/12) You have to use the formula x=-b/2a
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