Respuesta :

syed514
x=a(t−sint)

y=a(1−cost)
the area, as usual, will be
∫ydx
but notice that
dx / dt=a(1−cost)→dx=a(1−cost)dt

so the integral becomes
∫ydx=∫2π(upper integral limit) 0 (lower integral limit) a^2(1−cost)^2dt

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