finMericetug finMericetug
  • 26-11-2016
  • Mathematics
contestada

Find the sum to n terms of the series 0.6+0.66+0.666+.....................

Respuesta :

alsteva alsteva
  • 30-11-2016
We have
[tex]0.6+0.66+0.666+0.6666[/tex]

Let's take 6 out from the series
[tex]6(0.1+0.11+0.111+0.1111+....[/tex]

Now multiply and divide by 9
[tex]\frac{6}{9}(0.9+0.99+0.999+0.9999+....[/tex]

[tex]\frac{6}{9}(1-0.1+1-0.01+1-0.001+1-0.0001+.... \\ \\\frac{6}{9}(1-10^{-1}+1-10^{-2}+1-10^{-3}+...[/tex]

all 1s add up to n
[tex]\frac{6}{9}(n-\frac{1}{10}\times \frac{1-(\frac{1}{10})^{n+1}}{1-\frac{1}{10}})[/tex]

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