Correct answer is TRUE.
[tex]\tan \alpha= \frac{x}{y}
\\
\\ \alpha=45^o \Rightarrow x=y \Rightarrow \frac{x}{y} =1\Rightarrow \tan \alpha=1
\\
\\ 45^o\ \textless \ \alpha\ \textless \ 90^o \Rightarrow x\ \textgreater \ y \Rightarrow \frac{x}{y} \ \textgreater \ 1\Rightarrow \tan \alpha\ \textgreater \ 1[/tex]
