Terrezfalizza Terrezfalizza
  • 26-11-2016
  • Mathematics
contestada

Find the total distance traveled during the first 8s for v = 3t^2 - 24t + 36

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alsteva alsteva
  • 29-11-2016
Velocity is the derivative of distance, so integrate:

[tex]v = 3t ^{2} - 24t + 36[/tex]

And input 8 for t.

Find

[tex]\int\limits_{0}^{8} (3t^2 - 24t + 36) dt \\ \\t^3|^8_0-12t^2|_0^8+36t|_0^8 \\ \\8^3-0^3-12(8^2-0^2)+36(8-0) \\512-768+288 \\32 [/tex]
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