Respuesta :

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2≤x≤8 −4≤f′(x)≤5 f is continuous in differentable on [2,8] so we know there is c btw 2 and 8 such that f′(c)=f(8)−f(2)/8−2 And we know −4≤f′(c)≤5 => we have −4≤ f(8)−f(2)/8−2 ≤5

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