Mi2ranilarodran Mi2ranilarodran
  • 26-11-2016
  • Chemistry
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Phosphorus-32 has a half-life of 14.3 days. How many milligrams of phosphorus-32 remain after 71.5 days is you start with 4.00 mg of the isotope?

Respuesta :

scme1702
scme1702 scme1702
  • 29-11-2016
We first calculate the decay constant, λ
λ = ln(2) / half life
λ = ln(2) / 14.3

The decay equation is:
N = N(initial) x exp(-λt)
N = 4 x exp(-ln(2)/14.3 x 71.5)
N = 0.125 mg will remain
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