Answer:
Given circle:
The center is at (4, 0) and the radius is 5 units
Lets find the distance from (7, 2) to the center of the circle:
- [tex]d = \sqrt{(7 - 4)^2 + (2 - 0)^2} = \sqrt{9+4} = \sqrt{13} < 5[/tex]
Since d < 5, the point (7, 2) lies inside the circle
