Respuesta :

dsdrajlin

Answer:

2.49 M

Explanation:

Step 1: Given data

  • Mass of AlCl₃: 150. g
  • Volume of solution: 0.450 L

Step 2: Calculate the moles AlCl₃ (solute)

The molar mass of AlCl₃ is 133.34 g/mol.

150. g × 1 mol/133.34 g = 1.12 mol

Step 3: Calculate the molar concentration of AlCl₃

Molarity is equal to the moles of solute divided by the liters of solution.

M = 1.12 mol/0.450 L = 2.49 M

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