Answer:
(2, 1 )
Step-by-step explanation:
Using differential calculus
Given
y = (2x - 3)² = 4x² - 12x + 9 , then
[tex]\frac{dy}{dx}[/tex] = 8x - 12
[tex]\frac{dy}{dx}[/tex] is the measure of the gradient of the tangent , thus equate to 4
8x - 12 = 4 ( add 12 to both sides )
8x = 16 ( divide both sides by 8 )
x = 2
Substitute x = 2 into the equation for corresponding y- coordinate
y = (4 - 3)² = 1² = 1
The gradient of tangent is 4 at (2, 1 ) on the curve
