Respuesta :

manissaha129

Answer:

What is the net force on the block shown above?

★F(app) =25N, F(G) =60N

★F(app) =95N, F(G)=60N✓

★F(app) =60N, F(G) =25N

★F(app) =60N, F(G) =95N

Explanation:

Net Force 60N Right

→F(app) = 60+F(frict) = (60+35) = 95 N

→F(N)= F(G) = 60 N

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