Answer:
BeSe.
Explanation:
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In this case, since ionic compounds formed between metals in group 2A and nonmetals in groups 6A have 1 as the subscripts of the ions forming the compound as they have the same charge number, but opposite sign, for Beryllium and selenium we have:
[tex]Be^{2+}Se^{2-}\\\\BeSe[/tex]
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