au6narma2nbtievs au6narma2nbtievs
  • 31-10-2016
  • Mathematics
contestada

Determine the type and number of solutions of 4x^2-5x+1=0

a. two real solutions
b. one solution
c. tow imaginary solutions

Respuesta :

brainzonly
brainzonly brainzonly
  • 09-11-2016

4x^2-5x=-1

[tex] \sqrt{4x^2-5x} = \sqrt{-1} [/tex]4x^2-5x+1=0

4x+2.24x=1

6.24x=1

x= 0.16025641025641025641025641025641


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connerdirienzo
connerdirienzo connerdirienzo
  • 11-01-2021

Answer:

Two real solutions (x' = -1 and x'' = -1/4)

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