xiaojie320 xiaojie320

30-12-2020
Mathematics

contestada

Solve for x:abx²-(a⁴+b⁴)x+a³b³=0

Respuesta :

ChoiSungHyun ChoiSungHyun

30-12-2020

Step-by-step explanation:

abx² - (a⁴ + b⁴)x + (a³b³) = 0

(ax - b³)(bx - a³) = 0

Therefore x = b³/a or x = a³/b.

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