Answer:
1.22×10^38Joules
Explanation:
Rotational Kinetic energy is expressed as I = 1/2MR²
M is the mass of the earth
R is the radius of the earth
Given
M = 5.98 x 10^24 kg
R = 6.38 x 106 m
Substitute
I = 1/2(5.98 x 10^24)(6.38 x 10^6)²
I = 1/2(243.41)×10^{24+12}
I = 1/2(243.41)×10^36
I = 121.71×10^36
I = 1.22×10^38
Hence the rotational kinetic energy of Earth on its axis is 1.22×10^38Joules
