asimkhankhan897 asimkhankhan897
  • 27-11-2020
  • Engineering
contestada

How much energy in joule is added to a 12 g of sample of aluminum (c=0.897 J/g ◦C) to raise the temperature from 20 ◦C to 45 ◦C?

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hamuniruha
hamuniruha hamuniruha
  • 27-11-2020

Answer:

269.1J

Explanation:

m = 12g

c = 0.897J/g°C

∆T = 45 - 20 = 25°C

H = mc∆T = 12 × 0.897 × 27 = 269.1J

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