Answer:
a' = 2a
Explanation:
The acceleration during this circular motion is the centripetal acceleration. Initially, the acceleration will be given as:
a = v²/r --------------------- equation (1)
Where,
a = centripetal acceleration at outer edge
v = speed of merry go round = 5 m/s
r = distance from center of round to person (outer edge)
Now, when the person moves half way towards center. Then, the acceleration becomes:
a' = v²/r'
where,
r' = r/2
Therefore,
a' = v²/(r/2)
a' = 2v²/r
using equation (1):
a' = 2a
