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26-11-2020
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A particle of mass 2.5kg is moviy at a steady speed of 12m/s.when it meets with a fixed resistance of 10N.how long does it take to come to rest?

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26-11-2020

Answer:

3s

Explanation:

Newtons 2nd Law:

F = m × a

F = force (N)

m = mass (kg)

a = acceleration (m/s²)

-10 = 5/2 × a

a = -4m/s²

12/4 = 3

3s to come to test

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