Answer:
[tex]6.5714\text{M}[/tex]
Explanation:
Number of moles of NaCl = 2.3 moles
Volume = 350 mL = [tex]350\times 10^{-3}\ \text{L}=0.35\ \text{L}[/tex]
Molarity is given by
[tex]M=\dfrac{\text{Number of moles of NaCl}}{\text{Volume}}[/tex]
[tex]\Rightarrow M=\dfrac{2.3}{0.35}[/tex]
[tex]\Rightarrow M=6.5714\text{M}[/tex]
Molarity of the solution is [tex]6.5714\text{M}[/tex]
