Answer:
[tex]r=-\frac{1}{11}[/tex]
Step-by-step explanation:
[tex]4-5(1r) -2 = 3 +6r\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\\\4-5r-2=3+r\\\\\mathrm{Group\:like\:terms}\\\\-5r+4-2=3+6r\\\\-5r+2=3+6r\\\\\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}\\-5r+2-2=3+6r-2\\\\Simplify\\-5r=6r+1\\\\\mathrm{Subtract\:}6r\mathrm{\:from\:both\:sides}\\-5r-6r=6r+1-6r\\\\Simplify\\\\-11r=1\\\\\mathrm{Divide\:both\:sides\:by\:}-11\\\\\frac{-11r}{-11}=\frac{1}{-11}\\\\Simplify\\\\r=-\frac{1}{11}[/tex]
