Answer:
Step-by-step explanation:
[tex]4(x+3)-7\geq x+3(x+1)\\4x + 12 - 7 \geq x+ 3x+ 3\\[/tex]
isolate x
[tex]4x + 5 \geq 4x+ 3\\5 - 3 \geq 4x - 4x\\2\geq 0[/tex]
since 2 is greater than 0, this is a true statement, meaning that for any x, the inequality is true. it is always true
x : (-∞, ∞)
