Answer:
(2x^2-4y+2y^2)(3x-4)
Step-by-step explanation:
(2x2−4y+2y2)(3x−4)
=(2x2+−4y+2y2)(3x+−4)
=(2x2)(3x)+(2x2)(−4)+(−4y)(3x)+(−4y)(−4)+(2y2)(3x)+(2y2)(−4)
=6x3−8x2−12xy+16y+6xy2−8y2
=6x3+6xy2−8x2−12xy−8y2+16y
