Answer:
[tex]y=-\,(x+1)^2+3[/tex]
Step-by-step explanation:
Notice that the vertex of the parabola is at (-1, 3), so we can start the expression of the quadratic in vertex form as:
[tex]y=a\,(x--1)^2+3\\y = a\,(x+1)^2+3[/tex]
we can now find the coefficient "a" by using another point the parabola goes through, like for example (0,2):
[tex]y = a\,(x+1)^2+3\\2=a\,(0+1)^2+3\\2=a+3\\a=2-3\\a=-1[/tex]
So the final expression for the parabola in vertex form is:
[tex]y=-\,(x+1)^2+3[/tex]
