arthersannicolas7 arthersannicolas7
  • 27-10-2020
  • Mathematics
contestada

What is the equation of the line that is perpendicular to 2x + 4y = 1 and that passes through the point (6,8)?

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altavistard
altavistard altavistard
  • 28-10-2020

Answer:

2x - y = 4

Step-by-step explanation:

The base line is 2x + 4y = 1.  To obtain a general formula for lines perpendicular to this "standard form" equation, interchange  and y and replace the '1' with 'C:'

2y - 4x = C

Since the line in question passes through the point (6, 8), we substitute 8 for y and 6 for x, obtaining:

2(8) - 4(6) = C.  Then C = 16 - 24, or  = -8.

The desired equation is

2y - 4x = -8, or

4x - 2y = 8, or (after reduction)

2x - y = 4

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