[tex]d=0,7918\frac{g}{mL}\\
V=10mL \ \ \ \ \ \ \ \ \ \ \ m=dV=0,7918\frac{g}{mL}*10mL=7,918g\\\\
6,02*10^{23} \ \ \ \ \ \ \ \Rightarrow \ \ \ \ 32g\\
N_{x} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \Rightarrow \ \ \ \ 7,918g\\\\
N_{x}=\frac{6,02*10^{23}*7,918g}{32g}\approx1,49*10^{23}[/tex]
