cindy1994090
cindy1994090 cindy1994090
  • 26-09-2016
  • Mathematics
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Determine whether the sequence converges or diverges.
If it converges, find the limit. an=ln(2n^2 +1) - ln(n^2 +1)

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caylus
caylus caylus
  • 26-09-2016
Hello,
[tex]$ \lim_{x \to \infty} Ln(\frac{2x^2+1}{x^2+1}) =Ln(2)[/tex]
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