lellea
lellea lellea
  • 27-09-2020
  • Mathematics
contestada

Little help please? It would be much appreciated :D

Little help please It would be much appreciated D class=

Respuesta :

samkr14
samkr14 samkr14
  • 27-09-2020

Answer:

[tex]\frac{12ac^1^4}{b^3}[/tex]

Step-by-step explanation:

[tex]\frac{(a^{2}b^{4}c)^2 (6a^3b)(2c^5)^3}{4a^6b^1^2c^3}[/tex]

[tex]\frac{(a^4b^8c^2)(6a^3b)(8c^1^5)}{4a^6b^1^2c^3}[/tex]

[tex]\frac{48a^{7}b^9c^1^7}{4a^6b^1^2c^3}[/tex]

[tex]\frac{12ac^1^4}{b^3}[/tex]

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