lia08wilson lia08wilson
  • 26-09-2020
  • Mathematics
contestada

(4•6/2)v+10=4^3v+10 solve

462v1043v10 solve class=

Respuesta :

Аноним Аноним
  • 26-09-2020

Answer:

v=0

Step-by-step explanation:

Solve what is in the parentheses, then the exponents: 12v+10=64v+10

Subtract 64v from both sides: -52v+10=10

Subtract 10 from both sides: -52v=0

Divide by -52: v=0

Answer Link
abagailmae11
abagailmae11 abagailmae11
  • 26-09-2020

(4•6/2)v + 10 = 4^3v + 10

(24/2)v + 10 = 4^3v + 10

12v + 10 = 64v + 10

-12v -12v

10 = 52v + 10

-10 -10

0 = 52v

/52 /52

V= 0

Answer Link

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