Answer:
The 10th term of the GP is 2560.
Step-by-step explanation:
It is given that,
The first term of the GP, a = 5
Common ratio, r = 2
We need to find the 10th term of the GP. The nth term of a GP is given by :
[tex]T_n=ar^{n-1}[/tex]
Put n = 10
[tex]T_{10}=5\times 2^{10-1}\\\\T_{10}=2560[/tex]
So, the 10th term of the GP is 2560.
