Answer:
13
Explanation:
From the dilution formula;
C1V1 = C2V2
C1= concentration of the stock solution = 0.2 M
V1 = volume of the stock solution = 50.0 ml
C2= concentration of the diluted solution= the unknown
V2= volume of diluted solution= 100 ml
C2= C1V1/V2
C2= 0.2 × 50/100
C2= 0.1 M
But
pOH= -log[OH^-]
But [OH^-] = 0.1 M
pOH= -log [0.1]
pOH= 1
Since;
pH +pOH = 14
pH= 14 - pOH
pH= 14- 1
pH= 13
