Answer:
f^-1(x) = x/2 -1
Step-by-step explanation:
[tex]f(x) = 2x + 2\\\\f^-^1 (x) = ?[/tex]
Let y equal to the given equation ;
[tex]y = 2x+2\\[/tex]
Solve for x ;
[tex]y-2 = 2x\\Divide \:both\:sides\:of\:the\:equation\:by \:2\\\\\frac{y}{2} - \frac{2}{2} = \frac{2x}{2} \\\\\frac{y}{2} -1 =x\\\\x = \frac{y}{2} -1[/tex]
Change the y back to x
[tex]x = \frac{x}{2} -1 \\\\f^-^1(x) = \frac{x}{2} -1[/tex]
